求∫1/20[(1-x)/√1-x2]dx
【正确答案】：∫1/20[(1-x)/√1-x2]dx =∫1/20[1/√(1-x2)]dx+1/2∫1/20[d(1-x2)]/√(1-x2) =arcsinx∣1/20+1/2×[1/-(1/2)+1](1-x2)-(1/2)+1∣1/20 =π/6+√(1-1/4)-√1=π/6+√3/2-1
求∫1/20[(1-x)/√1-x2]dx
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