计算行列式|aa+da+2d||a+da+2da||a+2daa+d|

计算行列式
|aa+da+2d|
|a+da+2da|
|a+2daa+d|
【正确答案】：解： |a a+d a+2d| |a+d a+2d a| |a+2d a a+d| = |3(a+d) a+d a+2d| |3(a+d) a+2d a| |3(a+d) a a+d| =3(a+d) |1 a+d a+2d| |1 a+2d a| |1 a a+d| =3(a+d) |1 a+d a+2d| |0 d -2d| |0 -d -d| =3(a+d)[-d²-2d²]=-9d²2(a+d)